### Native American Day Math Contest - ENDED

Oct 9 is Native American Day (also known as Indigenous People's Day) .  To celebrate this occasion, we had an Operator Game Contest.

Thanks for participating in our Native American Day Math Contest.  There were many different answers to both questions with many answers, creative and unexpected.   It was amazing that we have to create a new category, Da Vinci award, for the most creative answer.  There were so many good answers so we decided to list the top 3 answers for each question (in term of points they earned)

Problem A (1, 2, 6, 8 with target of 2)

Problem B (3, 10, 12, 13 with target of 10)
The winners are

Youth Division:  Ashley Wang
Da Vinci Award : Allen Li, for the most creative answer: on Problem B (the 1st answer for Problem B listed above)

Check back here later this month for our Halloween Day Math Contest or follow us on our twitter feed (@wonderlandmath) for contest information when it is available.  Even you do not have the answer with the most points, you are growing your mind by working on them.  Great jobs, everyone.

Operator Game is a fun and creative way to play with numbers. The goal of the Operator Game is to create an equation to reach the target number from 4 given numbers using a set of allowed operators.

Rules:

Operators allowed and points:

·       1 point: addition (+), subtraction (-).

·       2 points: multiplication (*), division (/).

·       3 points: exponent (2^3 or exp(2,3)), square root (sqrt(4))

Requirements: Each given number is used exactly once. No other numbers can be used. The same operator cannot be applied repeatedly if the result is the same or infinitely to get a converging number to avoid infinite points.

Goal: Find an expression with as many points as possible, using the given 4 numbers exactly once and the allowed operators to produce the target number.

Examples:

Numbers given are 2,3,4,5. Target number: 7

Possible solutions:

• Expression A: 5+((2+4)/3) = 7. Operators used: +, +, /. Total poins: 1,1,2 => 4
• Expression B: 3+5-(sqrt(4)/2) = 7. Operators used: +,-,sqrt, /. Total points: 1,1,3,2 => 7
• Expression C: 3+5-sqrt(sqrt(4)/2)) = 7. Operators used: +,-,sqrt,sqrt,/. Total points: 1,1,3,3,2 => 10
• Expression D: 3+5-sqrt(sqrt(sqrt(sqrt(4)/2)))) = 7. => Illegal expression since sqrt() was repeatedly applied to 1.
• Expression E: Exp(5 + sqrt(4),sqrt(3-2)) = 7. => 12 points.

Contest problems:

Problem A:

Numbers given: 1, 4, 6, 8.         Target number: 2.

Problem B:

Numbers given: 3, 10, 12, 13.         Target number: 10.

For youth under 18 years old, submit your answers for Problem A and B here.

Winner Board: To win a recognition on the winner board, please submit your expressions by midnight Sunday, Oct. 8, 2017.

Winner Prize:

Like it?  Join us in our upcoming "Logic, Patterns, and Problem Solving" Class

Any question? Email Contest@WonderlandMath.com.

### Tips on Operator Game

 Tips on the Operator Game: ·        Square Root: sqrt(4) = 2 because 4 = 2*2. Sqrt(9) = 3. Sqrt(100) = 10. ·        Exponent: 2^3 = 2 * 2 * 2. 5^2 = 5 * 5 = 25. Example 1: Numbers given are 2,3,4,5. Target number: 7 Expression A: 5+((2+4)/3) = 7. Operators used: +, +, /. Total poins: 1,1,2 => 4 Expression B: 3+5-(sqrt(4)/2) = 7. Operators used: +,-,sqrt, /. Total points: 1,1,3,2 => 7 Expression C: 3+5-sqrt(sqrt(4)/2)) = 7. Operators used: +,-,sqrt,sqrt,/. Total points: 1,1,3,3,2 => 10 Expression D: 3+5-sqrt(sqrt(sqrt(sqrt(4)/2)))) = 7. => Illegal expression since sqrt() was repeatedly applied to 1. Expression F: Exp(5 + sqrt(4),sqrt(3-2)) = 7. => 12 points. Other ways to make 7: 2^3 – sqrt((5-4)) = 7. => 8 points. 2*3+sqrt(5-4)=7. => 6 points 3*(2*sqrt(4))-5 => 8 poins.